Ar9Jim 6,520 Posted December 24, 2023 Posted December 24, 2023 (edited) There are a couple equations to understand the physics Bob has leveraged. I'm not a designer but have asked Bob many questions in an effort to understand how and why he does what he does, to make products that produce a powerful, musical, accurate performance, often lighter in weight at fair prices over the years. Here are facts Bob refers to for reference: W = V squared / R Here is a calculator - http://www.csgnetwork.com/ohmslaw2.html V X A = W. Here is a calculator - https://convert-formula.com/a-v-w Power increases to the square of voltage. It's a big deal. Here is an example: If amp A can produce 100v at 8ohms its wattage is 1250w If amp B can produce 30% more voltage 133v at 8 ohms, its power goes up by 90% to 2211w and the amp doesn't necessarily gain weigh or cost. As the physics work, increasing voltage can have benefits in weight reduction. This is why the high voltage power lines overhead run up to 765,000 volts and carry huge power over long distances on small wires with minimal losses. At lower voltage the lines would be the size of oil pipeline in diameter and run hot with high losses flowing massive current. Voltage equals pressure. You can think of Bob's designs as 'high pressure' for a bit easier understanding of what Carver leverages and what he feels sounds best after decades of study at the physics level of electronics, sound and the ear brain interface. Bob has a long studied philosophy of using higher voltage power supply designs than normally found in solid state or tube amplifiers. Carver designs power supplies that act springy and bouncy, as he has determined these design types to sound the best. More about springy vs stiff power supplies in another post, 'Bob Carver Power Supplies - Stiff vs bouncy and springy.' What sounds best? Edited December 25, 2023 by Ar9Jim
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